N atoms of isotopes phosphorus-32 undergo radioactive decay. It decays to a non radioactive sulphur-32. Calculate in terms of N, the number of phosphorus-32 atoms remaining at the end of the 60 days, given that the half life of the isotope is 15 days.
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Answer:
15 days --> 1 half-life
30 days --> 2 half-life
45 days --> 3 half-life
60 days --> 4 half-life
so,
N --> N/2 --> N/4 --> N/8 --> N/16
Thus, N/16 of phosphorus-32 atoms is left at the end of the 60 days
