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Showing posts with label O lvl Phy: Electromagnetic Effects. Show all posts
Showing posts with label O lvl Phy: Electromagnetic Effects. Show all posts

O lvl Phy: Force on a current carrying conductor

RI 2004 Prelims P2 Q6

The diagram below shows an end-on view of a rectangular coil that is free to rotate about an axis between two magnetic poles. Current is passed into the coil via end X and out of the coil via end Y.



(a) Explain the origin of the force acting on end X of the coil, that is, how the force is produced.

(b)
(i) On the figure, draw the instantaneous forces acting on X and Y.
(ii) State how the size of the turning moment on the coil is changing at the instant shown in the figure.
(iii) Suggest one modification that can be made to the coil in the figure in order to obtain larger turning moments in general.

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Answer:

(a) A current carrying coil produces a magnetic field. This magnetic field interacts with the magnetic field from the magnet to produce regions of weaker and stronger magnetic fields. Such different regions of field strength causes resultant force to be produced.


(b)
(i)


(ii) The size of the turning moment decreases since the perpendicular distance from the axle of rotation decresaes when the coil approaches vertical position.

(iii) Wind more turns of wires on the coil or win the coil around an armature (soft iron core)


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O lvl Phy: Electromagnetic Induction

June 1989 P2 Q12

(a) The figure below shows an arrangement of apparatus which can be used to demonstrate electromagnetic induction. Coil A is connected to a battery as shown and coil B is connected to a sensitive centre-zero galvanometer. Coils A and B are placed close together.



State and explain what is observed
(i) when switch S is closed and remains closed,
(ii) when S is opened again.

(b)
(i) The experiment in (a) is repeated with a soft-iron rod placed in both coils. State and explain one difference in the observations which would be made.
(ii) In what way, if any, would the observations change if the soft iron rod is removed and a large sheet of soft iron is placed between the coils at right angles to the line joining coils A and B?

(c)
(i) Draw a labelled diagram to illustrate the structure of a simple transformer.
(ii) State and explain one reason why the design of the transformer you have drawn is better than the arrangement of coils shown above.

(d) An ideal transformer is to have an output of 12 V. Assuming that the input voltage is 240 V and that there are 3000 turns on the primary coil, calculate the number of turns required on the secondary coil.

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Answer:

(a)
(i) When the switch is closed a momentary deflection of the galvanometer pointer is noticed. A magnetic field is caused by the current in the coil A, causing a change in the magnetic flux cutting the coil B. This change induces an e.m.f. across B for a while.

When S remains closed, the pointer remains at O of the galvanometer scale as there is no induced current in B because the magnetic flux cutting the coil does not change.

(ii) When S is opened, the magnetic flux cutting the coil B decreases. This change of magnetic flux causes an e.m.f. in the opposite direction. Hence a momentary deflection in the opposite direction is observed in the galvanometer.


(b)
(i) When a soft iron rod is placed through the coils, greater momentary deflections are recorded in the galvanometer. Since magnetic lines of force pass through soft iron more easily than through air, they are concentrated from the coil A to the coil B. The rate of change of flux cutting the coil increases.

(ii) If a large sheet of iron is placed between coils, it acts as a magnetic screen. There will not be any deflection of the pointer in the galvanometer.


(c)
(i)


(ii) The closed soft iron core concentrates almost all the magnetic lines of force from the primary into the secondary coil. The rate of change of flux cutting the secondary will be greater than in the coil without the soft iron rod. Hence a greater e.m.f. is induced in the secondary.

(d)
Number of turns in secondary / number of turns in primary = output e.m.f. / input e.m.f.
n / 3000 = 12 / 240
n = 150

Hence, number of turns in the secondary coil = 150.


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O lvl Phy: Electromagnetic Induction

Catholic High 2004 Prelims P2 Q9b

The figure below shows a coil of wire wound on a piece of soft iron. A magnet is rotated in the gap in the soft iron as shown. When the magnet rotates, the lamp connected to the coil glows. The magnet takes 0.20s to make one complete revolution.



(i) Explain why the lamp glows when the magnet rotates.
(ii) Describe 2 alterations that can be made to the parts of the apparatus for the lamp to glow more brightly.
(iii) If the U-shaped soft iron is removed, would the lamp stil lglow when the magnet rotates? Explain your answer.
(iv) The lamp is marked 6.0 V, 36 W. Explain this statement.

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Answer:

(i) There is an induced emf generated at the ends of the coil, producing a current in the lamp due to changing magnetic flux linkage produced when the coil rotates.

(ii) Any 2
1) Increase the number of turns of the coil.
2) Rotate the magnet faster
3) Use a stronger magnet

(iii) Yes, there will still be a changing magnetic flux linkage, but the glow is weaker due to poorer flux linkage.

(iv) The lamp requires a normal working voltage of 6.0 V for it to convert energy into light at a rate of 36 J per second.


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