On a particular day, the atmospheric pressure at sea level was 102 000 Nm². at the same time, a mercury barometer placed at the top of the mountain indicated 0.6m Hg. Assume that the acceleration due to gravity remained constant. (density of mercury = 13 600 kg/m³)
If the density of the air between the top of the mountain and the sea level is 1.2 kg/m³, determine the height of the mountain top above sea level
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Answer:
Pressure at top of mountain = 0.6 * 10 * 13600 Pa = 81600 Pa
Pressure at sea level = 102000 Pa
Difference in pressure = 102000 - 81600 = 20400Pa
This difference in pressure = height * density of air * g
so, 20400 = height * 1.2 * 10
height of mountain = 1700 m
