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O lvl E Maths: Arithmetic

RGS Prelim 1997 Q8

A man buys 50 cartons of canned drinks at 30 cents per can. Each carton contains 24 cans and 20% of the cans are leaking.

(i) What should be the selling price of each of the remaining cans if he wants to make a profit of 60%?

(ii) If he only manages to sell 500 cans, what is the percentage loss?
(assuming that he cannot sell the balance)

*************************

Answer:



(i) Num of sellable cans = 50 * 24 * 80% = 960 cans (because 20% is not sellable)

Cost price = 50 * 24 * $0.30 = $360


To make a profit of 60%, he should sell for a total of $360 * 1.6 = $576

Hence, selling price for each can should be $576 / 960 = $0.60


The selling price should be 60 cents for each of the remaining cans if he wants to make a profit of 60%.



(ii) If he manages to sell 500 cans, he would have 500 * $0.60 = $300

There is a loss of $360 - $300 = $60


Percentage loss = 60/360*100 = 16.67%




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