Question from http://www.sgforums.com/forums/2297/topics/331427
A point B is 500 m due North of a point A. Rahmat walks from A on a bearing of 325°.
Find Rahmat's distance from A when he is
(i) due West of B
(ii) equidistant from A and B
(iii) closest to B
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Answer:
(i) bearings of 325° = 35° anti-clockwise as shown:
Hence, distance from A = 500 / cos 35°
= 610.4 m
(ii) Diagram is as shown:
Distance from A = 250 / cos 35°
= 305.2 m
(iii) Diagram is as shown:
Distance from A = 500 * cos 35°
= 409.6 m
